You can put this solution on YOUR website!Y = 2x 4 y = 2 x 4 Use the slopeintercept form to find the slope and yintercept Tap for more steps The slopeintercept form is y = m x b y = m x b, where m m is the slope and b b is the yintercept y = m x b y = m x b Find the values of m m and b b using the form y = m x b y = m x b m = 2 m = 2Simple and best practice solution for y=2(x3)(x4) equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so
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(x-2)(y+2x-4)= x-2 ^3 y=x+a
(x-2)(y+2x-4)= x-2 ^3 y=x+a-Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyMaximize 5 3x 4y x^2 x y y^2 WolframAlpha Have a question about using WolframAlpha?
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Solution for y = 2x 4 y = x 2 Plot two lines by clicking the graph Click a line to delete it 10 8 7 5 4 10 9 8 3432 10 3 The derivative of x − 2 is 1 y'(x) = 3(x2 9)4(x −2)2 (x − 2)3 d dx (x2 9)4 Now we use the chain rule on the second term d dx (x2 9)4 = d du u4 du dx where u = x2 9 d du u4 = 4u3 y'(x) = 3(x2 9)4(x −2)2 (x − 2)24(x2 9)3X − 2 = 0 x 2 = 0 Add 2 2 to both sides of the equation x = 2 x = 2 x = 2 x = 2 Set x 1 x 1 equal to 0 0 and solve for x x Tap for more steps Set the factor equal to 0 0 x 1 = 0 x 1 = 0 Subtract 1 1 from both sides of the equation
8x2y2/4x3y3 Final result 2x5y5 Step by step solution Step 1 y2 Simplify —— 4 Equation at the end of step 1 y2 (((8 • (x2)) • ——) • x3) • y3 4 Step 2 Equation at the end of step 2 y2Which phrase best describes the translation from the graph y = (x 2)2 to the graph of y = x2 3?Divide 2, the coefficient of the x term, by 2 to get 1 Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^ {2}2x1=y41 Square 1 x^ {2}2x1=y3 Add y4 to 1 \left (x1\right)^ {2}=y3 Factor x^ {2}2x1
X^45x^24=0 \sqrt{x1}x=7 \left3x1\right=4 \log _2(x1)=\log _3(27) 3^x=9^{x5} equationcalculator y=2x4 en Related Symbolab blog posts High School Math Solutions – Quadratic Equations Calculator, Part 1 A quadratic equation is a second degree polynomial having the general form ax^2 bx c = 0, where a, b, and c2 units left and 3 units up 2 units left and 3 units down 2 units right and 3 units up 2 units right and 3 units down C What is the first step when rewriting y = 4x2 2x 7 in the form y = a (xRewrite the expression Multiply − 1 1 by 1 1 Subtract 1 1 from 4 4 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k,
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Two parabolas are the graphs of the equations y=2x^210x10 and y=x^24x6 give all points where they intersect list the points in order of increasing xcoordinate, separated by semicolonsGraph a function by translating the parent function Explanation Another way of finding the axis and vertex is to complete the square y = x2 − 4x 3 y = (x − 2)2 −1 for the vertex find the x value that makes the bracket = 0 x = 2 ⇒ y = −1 vertex (2, − 1) axis of symmetry simply the the xvalue above X = 2 with the graph as before
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The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy3=0 x 2 − 2 x − y − 3 = 0 This equation is in standard form ax^ {2}bxc=0 Substitute 1 for a, 2 for b, and 3y for c in the quadratic formula, \frac {b±\sqrt {b^ {2}4ac}} {2a} 求微分方程y'＋x＝√(x^2＋y)的通解 42 y=2/x3/x^3的导数 需要解题过程谢谢，知道怎么计算但是算不出来，就是计算过程出问Simple and best practice solution for y=x^34x^23x2 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework
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First type the equation 2x3=15 Then type the @ symbol Then type x=6 Try it now 2x3=15 @ x=6 Clickable Demo Try entering 2x3=15 @ x=6 into the text box After you enter the expression, Algebra Calculator will plug x=6 in for the equation 2x3=15 2(6)3 = 15 The calculator prints "True" to let you know that the answer is right More ExamplesA Stepbystep explanation Given the 2 equations y = 2x 4 → (1) y = x² x 2 → (2) Substitute y = x² x 2 into (1) x² x 2 = 2x 4 (subtract 2x 4 from both sides) x² x 6 = 0 ← in standard form (x 3) (x 2) = 0 ← in factored formPre Calculus Equations Inequalities Simultaneous Equations System of Inequalities Polynomials Rationales Coordinate Geometry Complex Numbers Polar/Cartesian Functions Arithmetic & Comp Conic Sections Trigonometry Calculus
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Select a few x x values, and plug them into the equation to find the corresponding y y values The x x values should be selected around the vertex Tap for more steps Replace the variable x x with 0 0 in the expression f ( 0) = − ( 0) 2 2 ( 0) − 4 f ( 0) = ( 0) 2 2 ( 0) 4 Simplify the result Find an answer to your question Solve the system of equations y=2x4 y=x^2x2 jle1042 jle1042 Mathematics High School answered Solve the system of equations y=2x4 y=x^2x2 2 See answers MrGumby MrGumby Answer The two intersections would be (3Step by step solution of a set of 2, 3 or 4 Linear Equations using the Substitution Method y=2x4;3y=x2 Tiger Algebra Solver
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For example, the polynomial x 2 y 2 3x 3 4y has degree 4, the same degree as the term x 2 y 2 However, a polynomial in variables x and y , is a polynomial in x with coefficients which are polynomials in y , and also a polynomial in y with coefficients which are polynomials in xX2 = 0 Approaching (0;0) along the yaxis (x = 0), lim (x;y) !(0;0) 2xy x2 2y2 = lim y 0 0 2y2 = 0 Approaching (0;0) along the line y = x, lim (x;y)!(0;0) 2xy x2 2y2 = lim x!0 2x2 3x2 = 2 3 The limit does not exist Example Find the limit lim (x;y)!(0;0) x2y x4 y2 if it exists Approaching (0;0) along the line y = mx, lim (x;y)!(0;051 Find the Vertex of y = x 2 2x1 Parabolas have a highest or a lowest point called the Vertex Our parabola opens up and accordingly has a lowest point (AKA absolute minimum) We know this even before plotting "y" because the coefficient of the first term, 1 , is positive (greater than zero) Each parabola has a vertical line of symmetry
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PLAY Match Gravity Which ordered pairs are in the solution set of the system of linear inequalities?Y=x3 y=x^22x4 A x3=x^2 B x3=x^22x4 C y=(x3)^22(x3) dragonpikachucharman dragonpikachucharman Mathematics College answered To solve x 2 3x – 4 = 0 subtract x 2 3x – 4 = 0 from y = x 2 3x – 4, The points of intersection of the parabola with the x axis are the points (4, 0) and (1, 0), whose x – coordinates (4, 1) is the solution, set for the equation x 2 3x – 4 = 0
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Find an answer to your question what is the result of substituting for y in the bottom equation?Swap sides so that all variable terms are on the left hand side Swap sides so that all variable terms are on the left hand side 2x4=y 2 x 4 = y Subtract 4 from both sides Subtract 4 from both sides 2x=y4 2 x = y − 4 Divide both sides by 2Y >1/2 x y
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Volume of the region bounded by y=x^24,y=2xx^2, y=0 rotated around y=2,2Graph y=x^24 y = x2 − 4 y = x 2 4 Find the properties of the given parabola Tap for more steps Rewrite the equation in vertex form Tap for more steps Complete the square for x 2 − 4 x 2 4 Tap for more steps Use the form a x 2 b x c a x 2Now, join the points by a smooth curve The curve so obtained, is the graph of y = x 2 3 x 2 Now, x 2 2 x 4 = 0 ⇒ x 2 3 x 2 − x 2 = 0 ⇒ y = x − 2 ∵ y = x 2 3 x 2 Thus the roots of x 2 2 x 4 = 0 are obtained from the points of intersection of y = x − 2 and y = x 2 3 x 2 Now, form the table for the line y
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x^3x^22x4 = (x1)(x^22x4) = (x1)(x1sqrt(3)i)(x1sqrt(3)i) First note that the sum of the coefficients is zero That is 1124 = 0 So x=1 is a zero and (x1) a factor x^3x^22x4 = (x1)(x^22x4) The remaining quadratic factor is of the form ax^2bxc with a=1, b=2 and c=4 This has discriminant Delta given by the formula Delta = b^24ac = 2^2(4*1*4) =2 (2xy)=2 (xy)4 Simple and best practice solution for 2 (2xy)=2 (xy)4 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework If it's not what You are looking for type in the equation solver your own equation and let us solve itAll equations of the form a x 2 b x c = 0 can be solved using the quadratic formula 2 a − b ± b 2 − 4 a c The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction x^ {2}2xy^ {2}2y3=0 x 2 − 2 x y 2 2 y − 3 = 0 This equation is in standard form ax^ {2}bxc=0
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Y=2x3eq 1 y=x2eq 2 so take the value of y from eq 2 and plug it into eq 1 (x2)=2x3 now take x's foundSimple and best practice solution for x^2y^22x4y3=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkGet stepbystep solutions from expert tutors as fast as 1530 minutes Your first 5 questions are on us!
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Transcribed Image Textfrom this Question Find the slope of the curve y = x^2 2x 4 at the point P (3, 1) by finding the limit of the secant slopes through point P (b) Find an equation of the tangent line to the curve at P (3, 1)// Plug this in for variable y in equation 2 2 4x 8• (2x4) = 8 2 12x = 24 // Solve equation 2 for the variable x 2 12x = 24 2 x = 2 // By now we know this much x = 2 y = 2x4 z = 3x5y // Use the x value to solve for y y = 2(2)4 = 0 // Use the x and y values to solve for z z = 3Question Y = X3 / 3 X2 / 2 2x 4 1 Find Y' = F'(x) 2 Find Critical Values X= 3 Find Critical Points (x,y) = (x,y) = 4 Find Intervals Of Xvalues Where Function Is Increasing 5 Find Intervals Of Xvalues Where Function Is Decreasing 6 Relative
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Y'*x (3*x^2x*y3*y^2)y* (4*x^2x*y4*y^2)=0 WolframAlpha Rocket science?Algebra Graph y=2 (x3)^24 y = 2(x − 3)2 − 4 y = 2 ( x 3) 2 4 Find the properties of the given parabola Tap for more steps Use the vertex form, y = a ( x − h) 2 k y = a ( x h) 2 k, to determine the values of a a, h h, and k k a = 2 a = 2 h = 3 h = 3 k = − 4 k = 4Get stepbystep solutions from expert tutors as fast as 1530 minutes
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